Answer:
A. 525 in squared
Step-by-step explanation:
Fundamentally, the area of a parellelogram such as this can be calculated the same way the area of a normal rectangle is calculated: Length x Width.
Thus,
(27 + 8) x 15 = Area
35 x 15 = Area
525 = Area
Don't forget your units! (Inches squared)
<span>Here is what I got for the first one.
MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|85-83|+|83-83|+|87-83|+|90-83|+|70-83|) =1/5(2+0+4+7+13)) =5.2
And for the second one I got,
MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|75-76|+|74-76|+|68-76|+|83-76|+|80-76|) =1/5(1+2+8+7+4)) =4.4
answer = 4.4
</span>
The answer in itself is 1/128 and here is the procedure to prove it:
cos(A)*cos(60+A)*cos(60-A) = cos(A)*(cos²60 - sin²A)
<span>= cos(A)*{(1/4) - 1 + cos²A} = cos(A)*(cos²A - 3/4) </span>
<span>= (1/4){4cos^3(A) - 3cos(A)} = (1/4)*cos(3A) </span>
Now we group applying what we see above
<span>cos(12)*cos(48)*cos(72) = </span>
<span>=cos(12)*cos(60-12)*cos(60+12) = (1/4)cos(36) </span>
<span>Similarly, cos(24)*cos(36)*cos(84) = (1/4)cos(72) </span>
<span>Now the given expression is: </span>
<span>= (1/4)cos(36)*(1/4)*cos(72)*cos(60) = </span>
<span>= (1/16)*(1/2)*{(√5 + 1)/4}*{(√5 - 1)/4} [cos(60) = 1/2; </span>
<span>cos(36) = (√5 + 1)/4 and cos(72) = cos(90-18) = </span>
<span>= sin(18) = (√5 - 1)/4] </span>
<span>And we seimplify it and it goes: (1/512)*(5-1) = 1/128</span>
24) -10 to 25
25) 42
26) to much
27) also too much
don't get mad, this was only for 13 points so that's on you
Answer:
f(9)=-22-9(9)+20=-83
Step-by-step explanation:
f(9) means x = 9, Just substitute 9 into the function.
-9(9) = -81
-22-81+20 = -83
