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laiz [17]
3 years ago
10

I need answer ASAP Please

Mathematics
1 answer:
raketka [301]3 years ago
4 0

Answer:

3

6x10^8/2x10^8

= 3 times

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A sample of 18 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n
ki77a [65]

Answer:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

Step-by-step explanation:

a)

i.  x=- - - - - -

ii.  o=- - - - - -

iii.  Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.  

c) The statistics variable X  is a measure on a sample that is used as an estimate of the population mean.X  is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters  because the population standard deviation is known.

N(X, o/\sqrt{n})

So, the distribution is  

N(2, 0.12/\sqrt{16})

e)

i. The 90% confidence interval for the population mean weight of the candies is  1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is  1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part  is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

5 0
2 years ago
A department store sells a pair of shoes with an 56.3% markup. If the store bought the pair of shoes for $43.75, what is the sel
ella [17]

Answer:

The selling price for the shoes will be $68.35

Step-by-step explanation:

8 0
3 years ago
Using the probability scale, what is the probability that a red cube will be drawn when a cube is selected from a bag that has 5
dmitriy555 [2]

Answer:

D

Step-by-step explanation:

Probability is calculated by divided the amount of something you have by the total amount. In this case, 5 red cubes by 10 total cubes to get .5. This falls into evens in your probability scale.

5 0
2 years ago
Read 2 more answers
Find the length of side a.<br> please help?
GaryK [48]

Answer:

Hello! I believe your answer is a = 3

Step-by-step explanation:

a= \sqrt{5^{2}-4^{2} } = 3

Have a good day! - Zac

8 0
2 years ago
Read 2 more answers
Is 1/2x -1 equivalent to 2/3(3/4x-3/2)
jasenka [17]

Answer:

128273

Step-by-step explanation:

$2200/month 66253

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3 years ago
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