Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
Answer:
14
Step-by-step explanation:
You can solve using PEMDAS:
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
3(2+5)-5(3)+8=?
3(7)-5(3)+8=?
No exponents
3(7)-5(3)+8=?
21-15+8=?
No division
21-15+8=?
21-7=?
21-7=14
3(2+5)-5(3)+8=14
Answer:
Jimmy; 26
Step-by-step explanation:
PEMDAS
Parentheses Exponents Multiplication Division Addition Subtraction
6 + 4 * 10 / 2 = 6 + 40 / 2
6 + 40 / 2 = 6 + 20
6 + 20 = 26
26
1 is 1
2 is going to be -8x to the second minus 6 x
3 is 3 plus three x two minus seven x plus two xx 2 minus 6xto the 2
4 is 11
Answer:
72
Step-by-step explanation:
