let's firstly conver the mixed fractions to improper fractions and then get their product.
![\stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} ~\hfill \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{9}{2}\cdot \cfrac{5}{2}\cdot 6\implies \cfrac{270}{2}\implies 135](https://tex.z-dn.net/?f=%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B9%7D%7B2%7D%7D%20~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B5%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B9%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B5%7D%7B2%7D%5Ccdot%206%5Cimplies%20%5Ccfrac%7B270%7D%7B2%7D%5Cimplies%20135)
hmmm I take it that one can write that mixed as
.
is valid, not that it makes any sense.
x=ferns ; y=ivy
12x+8y=260
6x+15y=240
x=60 -(15/6)y
12(60+ (15/6)y + 8y = 260
x=60 -(15/6)y
720 - 30y + 8y = 260
x=60- (15/6)y
-30y +8y= 260-720 ==> -22y= -460
x=60 -(15/6)y
y= (-460)/(-22)= 20.9090909091
y=20.90
x=60 -(15/6)×20.90= 7.75
×(ferns)=7.75$
y(ivy)=20.90$
Dilation involves enlarging or reducing the size of a shape.
The scale factor of dilation is 1/6
From the complete question, the side lengths of corresponding sides of both triangles are:


This means that, the larger triangle is ABC, while the smaller triangle is AB'C'.
So, the scale factor of dilation from the larger triangle to the smaller triangle is:

This gives

Remove the common units

Reduce fraction

Hence, the scale factor of dilation is 1/6
Read more about dilation at:
brainly.com/question/3457976
A function is called linear if highest degree of the equation is 1.
Here, degree of x and y is 1 hence it's a linear function.
If line 3x + 4y = 24 cuts the x axis at point A, then point A is ur x intercept of line 3x + 4y = 24. To find the x int, sub in 0 for y and solve for x.
3x + 4y = 24
3x + 4(0) = 24
3x = 24
x = 24/3
x = 8....so point A is (8,0) <===
if line 3x + 4y = 24 cuts the y axis at point B, the point B is the y int. of 3x + 4y = 24. To find the y int, sub in 0 for x and solve for y
3x + 4y = 24
3(0) + 4y = 24
4y = 24
y = 24/4
y = 6......so point B is (0,6) <===
if point C is equidistant from point A and point B, then it is the midpoint.
midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
(8,0)....x1 = 8 and y1 = 0
(0,6)...x2 = 0 and y2 = 6
time to sub and solve
m = (8 + 0)/2 , (0 + 6)/2
m = (8/2),(6/2)
m = (4,3) <=== this is point C