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3 years ago

11

Find the number of terms, n, in the arithmetic series whose first term is 15, the common difference is 4, and the sum is 3219. P

ls I need help ASAP I will give top answer.
A. 33
B. 35
C. 37
D. 36

1 answer:

klio [65]3 years ago

6 0

Answer: 37

Step-by-step explanation:

I guessed on the quiz and got it right

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Insert 2 geometric means between -32 and 4

denis23 [38]

Answer:

16, -8

Step-by-step explanation:

Let the terms of the geometric sequence be $a, ar, ar^2, ar^3$ .

We know that $a=-32$ and thus, $-32r^3=4 \implies r=-1/2$ .

This means $ar=(-32)(-1/2)=16$ and $ar^2=-32(1/2)^2=-8$ .

6 0

1 year ago

The quadrilateral ABCD has area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.

inessss [21]

When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.
.. A = (1/2)*d₁*d₂
Substituting the given information, this becomes
.. 58 in² = (1/2)*(14.5 in)*d₂
.. 2*58/14.5 in = d₂ = 8 in

The length of diagonal BD is 8 in.

7 0

4 years ago

How do you get the answer 1 and 1/4-3/8

JulijaS [17]

U first find the common denominator which is 8

Then subtract to get 7/8

5 0

3 years ago

I need help on all the questions here

Slav-nsk [51]

They all are all math vocabulary

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3 years ago

Read 2 more answers

Joe has read 140 pages of his 300 page book what percentage has he read please show work

Lostsunrise [7]

140/300=14/30
14/30=7/15
So 7/15 is _
46.6%

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3 years ago