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Varvara68 [4.7K]
3 years ago
6

Solve x2 + 8x − 3 = 0 using the completing-the-square method.

Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0

The solutions of the equation x^{2}+8x-3=0 are \boxed{0.36\text{ and }-8.36}.

Further explanation:

Given:

The equation is x^{2}+8x-3=0.

Concept used:

A quadratic function is defined as a function with degree or the highest power of the variable as 2.

The standard form of the quadratic equation is,

\boxed{ax^{2}+bx+c=0}                     … (1)

The above equation is converted by completing square as follows:

\begin{aligned}x^{2}+bx+c+\left(\dfrac{b}{2}\right)^{2}-\left(\dfrac{b}{2}\right)^{2}&=0\\x^{2}+bx+\left(\dfrac{b}{2}\right)^{2}+c-\left(\dfrac{b}{2}\right)^{2}&=0\\ \left(x+\dfrac{b}{2}\right)^{2}+c-\left(\dfrac{b}{2}\right)^{2}&=0\end{aligned}  

Calculation:

The given equation is x^{2}+8x-3=0.

Now, add and subtract by 16 in the left hand side of the equation x^{2}+8x-3=0 and simplify as follows,

\begin{aligned}x^{2}+8x-3+16-16&=0\\ (x^{2}+8x+16)-3-16&=0\\ (x+4)^{2}-19&=0\\(x+4)^{2}&=19\end{aligned}  

Further simplify the above equation as follows,

\begin{aligned}(x+4)^{2}&=19\\x+4&=\pm \sqrt{19}\\x+4&=\pm 4.36\\x&=\pm 4.367-4\end{aligned}  

First take positive sign and obtain the value of x as follows:

\begin{aligned}x&=4.36-4\\&=0.36\end{aligned}  

Now, take negative sign and obtain the value of x as follows:

\begin{aligned}x&=-4.36-4\\&=-8.36\end{aligned}

The values of x are 0.36\text{ and }-8.36.

Therefore, the solutions of the given equation are 0.36\text{ and }-8.36.  

To check that 0.36 is the solution of the equation, substitute x=0.36 in the equation x^{2}+8x-3=0 as,

\begin{aligned}(0.36)^{2}+(8\times 0.36)-3\ _{=}^{?}\ 0\\0.1296+2.88-3\ _{=}^{?}\ 0\\0=0\end{aligned}  

Therefore, 0.36 is the solution of the equation x^{2}+8x-3=0.

To check that -8.36 is the solution of the equation, substitute x=-8.36 in the equation x^{2}+8x-3=0 as follows:

\begin{aligned}(-8.36)^{2}+(8\times (-8.36))-3\ _{=}^{?}\ 0\\69.8896-66.88-3\ _{=}^{?}\ 0\\0=0\end{aligned}

Therefore, -8.36 is the solution of the equation x^{2}+8x-3=0.

Learn more:

1. A problem on quadratic function brainly.com/question/1332667

2. A problem on parabola brainly.com/question/3213890

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Quadratic equation

Keywords: Quadratic equation, complete square, function, equations, degree, highest power, solution, standard form, x2+8x-3, variable.

lisabon 2012 [21]3 years ago
3 0
(a+b)^2=a^2+2ab+b^2\\------------------\\\\x^2+8x-3=0\ \ \ |add\ 3\ to\ both\ sides\\\\x^2+2x\cdot4=3\ \ \ |add\ 4^2\ to\ both\ sides\\\\x^2+2x\cdot4+4^2=3+4^2\\\\(x+4)^2=3+16\\\\(x+4)^2=19\iff x+4=-\sqrt{19}\ or\ x+4=\sqrt{19}\\|subtract\ 4\ from\ both\ sides\\\\\boxed{x=-4-\sqrt{19}\ or\ x=-4+\sqrt{19}}
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