Answer: 15
Step-by-step explanation:Do 27-12 and you get 15
Answer:
It would be <u>97.50</u> square deckles.
Step-by-step explanation:
Given:
On the distant plant, Mathology, a sports area covers 7400 yodels².
1 deckle = 75.9 yodels.
Now, to get the square deckles.
As given, 1 deckle = 75.9 yodels.
So, to get the square deckles by using conversion factor:
<em>75.9 yodels = 1 deckle.</em>
7400 yodels² = ![7400\div 75.9](https://tex.z-dn.net/?f=7400%5Cdiv%2075.9)
= ![97.50\ deckels ^2.](https://tex.z-dn.net/?f=97.50%5C%20deckels%20%5E2.)
Therefore, it would be 97.50 square deckles.
Can you please help me use this app I am new to this app
Answer:
C) ![A+\frac{2}{5}B](https://tex.z-dn.net/?f=A%2B%5Cfrac%7B2%7D%7B5%7DB)
Step-by-step explanation:
Given Equations:
A) ![\frac{2}{5}x+y=12](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7Dx%2By%3D12)
B) ![\frac{5}{2}y-x=6](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7Dy-x%3D6)
In order to eliminate
we need to multiply
to equation B and add it to A.
Multiplying
to B.
⇒ ![\frac{2}{5}\times (\frac{5}{2}y-x)=\frac{2}{5}\times 6](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%5Ctimes%20%28%5Cfrac%7B5%7D%7B2%7Dy-x%29%3D%5Cfrac%7B2%7D%7B5%7D%5Ctimes%206)
⇒ ![(\frac{2}{5}\times\frac{5}{2}y)-(\frac{2}{5}x)=\frac{12}{5}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B5%7D%5Ctimes%5Cfrac%7B5%7D%7B2%7Dy%29-%28%5Cfrac%7B2%7D%7B5%7Dx%29%3D%5Cfrac%7B12%7D%7B5%7D)
⇒ ![y-\frac{2}{5}x=\frac{12}{5}](https://tex.z-dn.net/?f=y-%5Cfrac%7B2%7D%7B5%7Dx%3D%5Cfrac%7B12%7D%7B5%7D)
Adding it equation A.
![\frac{2}{5}x+y=12](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7Dx%2By%3D12)
+ ![-\frac{2}{5}x+y=\frac{12}{5}](https://tex.z-dn.net/?f=-%5Cfrac%7B2%7D%7B5%7Dx%2By%3D%5Cfrac%7B12%7D%7B5%7D)
We get ![2y=\frac{72}{5}](https://tex.z-dn.net/?f=2y%3D%5Cfrac%7B72%7D%7B5%7D)
Thus
is eliminated.
So, the expression used to eliminate
is:
![A+\frac{2}{5}B](https://tex.z-dn.net/?f=A%2B%5Cfrac%7B2%7D%7B5%7DB)
Answer:
56
Step-by-step explanation:
The n th term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₆ = 17 and a₁₃ = 38, then
a₁ + 5d = 17 → (1)
a₁ + 12d = 38 → (2)
Subtract (1) from (2) term by term to eliminate a₁
7d = 21 ( divide both sides by 7 )
d = 3
Substitute d = 3 into (1) and evaluate for a₁
a₁ + 5(3) = 17
a₁ + 15 = 17 ( subtract 15 from both sides )
a₁ = 2
Thus
= 2 + (18 × 3) = 2 + 54 = 56