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igor_vitrenko [27]
4 years ago
10

A science fair poster is a rectangle 46 inches long and 36 inches wide. What is the area of the poster in square feet?

Mathematics
1 answer:
Aleksandr-060686 [28]4 years ago
6 0

Hello,

46 × 36 = 1 656 inches²

Bye :)

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Suppose the position of an object moving horizontally after t seconds is given by the following functions s=f(t), s equals f , o
Scilla [17]

Answer:

(a) The graph of position function is shown below.

(b) The velocity function is v(t)=-2t+4 and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(c) Velocity and acceleration of the object at t=1 are 2 and -2 respectively.

(d) The acceleration of the object is -2 when its velocity is zero.

(e) The speed is not increasing at any interval because the acceleration is constant.

Step-by-step explanation:

(a)

The given function is

f(t)=-t^2+4t-3; 0\leq t\leq 5

The position of an object moving horizontally after t seconds is given by

s=f(t)=-t^2+4t-3

The graph of position function is shown below.

(b)

Differentiate the position function with respect to time to find the velocity function.

v=f'(t)=-2t+4

Put v=0 to find the time when the object is stationary.

0=-2t+4

2t=4

t=2

The object is stationary at t=2 because the velocity of the object is 0 at t=2.

The velocity function is v(t)=-2t+4 and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(c)

The velocity function is

v=f'(t)=-2t+4

Substitute t=1 in the above function.

v=f'(1)=-2(1)+4=2

Differentiate the velocity function with respect to time to find the acceleration function.

a=f''(t)=-2

Substitute t=1 in the above function.

a=f''(1)=-2

Therefore the velocity and acceleration of the object at t=1 are 2 and -2 respectively.

(d)

The velocity of the object is 0 at t=2.

Substitute t=2 in the acceleration function to find the acceleration of the object when its velocity is zero.

a=f''(2)=-2

The acceleration of the object is -2 when its velocity is zero.

(e)

The acceleration function of the object is

a=f''(t)=-2

It is a constant function.

Therefore the speed is not increasing at any interval because the acceleration is constant.

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Answer:

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Step-by-step explanation:

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