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olya-2409 [2.1K]
3 years ago
12

Help please!!!!!!!!!!!!!!!

Mathematics
1 answer:
Likurg_2 [28]3 years ago
8 0
First, find the area of the whole square.

Area= Base times height= 48 times 96 = 4608

Next, find the area of ONE circle. The diameter is 12, so the radius would be 6

A=πr sqaured= 3.14 times 6 squared = 113.04

Next multiply by 3, since there are 3 circles.

113.04 times 3 =339.12

Subtract this value from the total area (4608)

4608-339.12=4268.88

ANSWER: 4268.88

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Answer:

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If we had a legit triangle, the law of sines would hold

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IF it did, we'd get different results depending on which set we used

∠F = 180 - 138 - 20 = 22°

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so really none is correct because we attempt to use trig calculations to a non-triangle.

12) AC² = 15² + 19² - 2(15)(19)cos120

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29.51270 / sin120 = 15/sinC

C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>

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