Answer:
-5x^4+8x^3-2x+1
Step-by-step explanation:
Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
Answer:
2nd option
Step-by-step explanation:
Repeatedly divide by 2 until the value 1 is reached
32 ÷ 2 = 16
16 ÷ 2 = 8
8 ÷ 2 = 4
4 ÷ 2 = 2
2 ÷ 2 = 1 ← finish here
Then
32 = 2 × 2 × 2 × 2 × 2
Answer:
116
Step-by-step explanation:
82 brownies sold for $1 each is $82 in total
140-82=58
each cookie is sold at $0.5 so we need to multiply the rest of the cash by 2
58×2=116
so he needs to sell 116 more cookies to reach his goal
