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3 years ago

Planes X and Y and points C, D, E, and F are shown.

Mathematics

1 answer:

jekas [21]3 years ago

6 0

Answer: Maybe B

Step-by-step explanation:

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16. m + 5(m - 1) =<br> How do u solve this

Ber [7]

Answer: 6m -5

Distribute 5
m+ 5m-5
Simplify
6m -5

3 0

2 years ago

Jade's room is 24 feet by 12 feet. She makes a scale drawing of 8 inches by 4 inches. What scale did she use?

8_murik_8 [283]

Answer:

d- 1 inch=3 feet

Step-by-step explanation:

24 feet÷_=8 inches, so the blank is 3

and that fits for 12 feet too.

12 feet ÷_=4 inches, so the black is 3

So, D

Hope this helps!

And welcome to the brainly family

5 0

2 years ago

Work out the number that is halfway between 27 times 38 and 33 times 38.

lutik1710 [3]

$27*38=1026\\
33*38=1254\\
x-between\ number\\
x=\frac{1026+1254}{2}\\
x=\frac{2280}{2}\\
x=1140$

4 0

3 years ago

Can you list all the properties of a parallelogram ?

nirvana33 [79]

Answer:

1. the interior angle measure of a parallelogram is 360 degrees

2. diagonal of a parallelogram bisect it into two congruent triangles

3. opposite angles of a parallelograms are congruent

4. a parallelogram has two pairs of parallel sides.

5. consecutive angles of a parallelogram are supplementary

Step-by-step explanation:

7 0

3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago