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Svet_ta [14]
3 years ago
12

What is equivalent fraction of 2/3

Mathematics
1 answer:
Serga [27]3 years ago
5 0
6/9
8/12
10/15
12/18
etc
etc
etc
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Find the area of the figure below by first finding the areas of the rectangle and triangle
Dmitrij [34]

Answer:

The total area is 45

Step-by-step explanation:

It's basically the same steps at the last problem

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Reuben jogs 2.25 miles every weekday.Every Saturday and Sunday ,he jogs 1.8 times as far. To the nearest hundredth , how many mi
lesya [120]

Answer:

  38.70 miles

Step-by-step explanation:

Each week, Reuben jogs ...

  (2.25 mi)(1 +1 +1 +1 +1 +1.8 +1.8) = (2.25 mi)(8.6)

Then in 2 weeks, he jogs ...

  2(2.25)(8.6) mi = 38.70 mi

Reuben jogs 38.70 miles in 2 full weeks.

4 0
2 years ago
Which number added to -14 will equal 9?​
Vlada [557]

Answer:

23

Add positive 14 and 9 to get 23

14 + 9 = 23

-14 + 23 = 9

8 0
1 year ago
How do you factor by grouping
Zanzabum
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</span>Step 1) Determine the product of AC (the coefficients in a quadratic equation)Step 2) Determine what factors of <span><span>a⋅c</span> sum to b</span>Step 3) "ungroup" the middle term to become the sum of the factors found in step 2Step 4) group the pairs.
3 0
3 years ago
Read 2 more answers
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
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