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3 years ago

Help- ;-; i am struggling ;-; I- cant do this--

Mathematics

1 answer:

Tems11 [23]3 years ago

4 0

Answer:

x is vertical *laying down* y in upward also (x,y) so ifthe first on would be anywhere on the y axis

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A. A line through P parallel to line L

m_a_m_a [10]

Answer:

b.a line through p intersecting line l

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3 years ago

Read 2 more answers

An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha

hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

$Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}$

Cross multiply

|AB|X Tan 15 =3000

|AB| = $\frac{3000}{Tan 15}$ =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

6 0

3 years ago

f(x) = square root ( x^4 -16x^2) let f be the function given by: . . a) Find the domain of f.. b) Find f '(x). c) Find the slope

Bond [772]

A ) The domain:
$x^{4} -16 x^{2} \geq 0 \\ x^{2} ( x^{2} -16) \geq 0 \\ x^{2} -16 \geq 0 \\ x^{2} \geq 16$
x ≤ -4 and x≥ 4 or: x ∈ ( - ∞ , - 4 ) ∪ ( 4 , + ∞ )
b ) f ` ( x ) = $\frac{1}{2 \sqrt{ x^{4} -16 x^{2} } } *( 4 x^{3} - 32 x ) = \\ = \frac{2x( x^{2} -8)}{ \sqrt{ x^{4}-16 x^{2} } }$
c ) The slope of the line normal to the graph at x = 5
m = -1 / f `(x)
f ` ( x ) = $\frac{10(25-8)}{ \sqrt{625-400} }= \frac{10*17}{15} = \frac{34}{3}$
m = - 3/34

8 0

3 years ago

In a certain population, 10% of the people can be classified as being high risk for a heart attack. a) Three people are randomly

VARVARA [1.3K]

Answer: 0.243.

Step-by-step explanation:

The probability in this case is approcimated by the probability distribution formula for random variables. This formula is denoted as:

P(X=r) = nCr * p^r * q^n-r

Where n = selected number to be sampled and in this case, n= 3

r = varied number of sample and in this case, r=1

P = probability of success and in this case p = 0.10

q = 1-p=1-0.1 = 0.9

P(X=1) = 3C1 × 0.1¹ × 0.9²

P(X=1) = 0.243.

3 0

3 years ago

Which values of a and b make the following equation true<br> (5x^7y^2) (-4x^4y^5) = -20x^a y^b

Nadya [2.5K]

In x^7•x^4, how many x’s are multiplied together? (There’s 7 in the first factor and 4 in the second.)

x^7•x^4 = x^__? This is your a-value.

Similarly, y^2•y^5 = y^__? How many y’s are there in total being multiplied? This is your b-value.

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3 years ago