All categories

3 years ago

In quadrant 2 , x is ? and y is ?

1 answer:

5 0

In quadrant 2, x is negative which means x < 0. Also, in quadrant 2, y is positive so y > 0.

An example point that is located in quadrant 2 is the point (-5, 8). Note how the first coordinate is -5 so x = -5 which is negative. Furthermore, the second coordinate is 8 meaning that y = 8 which is positive.

Quadrant 2 is the quadrant on the upper left-hand side of the four quadrants on the xy coordinate system.

You might be interested in

The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .

sammy [17]

Answer:

$32,24,18,\frac{27}{2} ,\frac{81}{8}$

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is $32,x,y,z,\frac{81}{8}$

Recall that term of a geometric sequence are generally in the form:

$a,ar,ar^2,ar^3,ar^4$

This implies that:

a=32 and $ar^4=\frac{81}{8}$

Substitute a=32 and solve for r.

$32r^3=\frac{81}{8}$

$r^4=\frac{81}{256}$

Take the fourth root to get:

$r=\sqrt[4]{\frac{81}{256} }$

$r=\frac{3}{4}$

Therefore $x=32*\frac{3}{4} =24$

$y=24*\frac{3}{4} =18$

$z=18*\frac{3}{4} =\frac{27}{2}$

8 0

3 years ago

Write a Rule for a Composite Function

zysi [14]

Answer:

Step-by-step explanation:

Observing that f has to be placed inside g, we can easily substitute x^2 - 3 in place of the x in x + 1, making it

(x^2 - 3) + 1 which equals

(x^2) - 2

5 0

3 years ago

Re-write the quadratic function below in Standard Form y = 9(x - 1)(x + 3)

Maksim231197 [3]

Y=9(x^2+3x-x-3)
y=9(x^2+2x-3)
y=9x^2+18x-27

4 0

3 years ago

Find the value of x such that the data set has the given mean 98, 122, 106, 112, 106, x; mean 114

Licemer1 [7]

Answer:

140

Step-by-step explanation:

$Mean=\frac{sum of datas}{number of data's}\\\\\frac{98+122+106+112+106+x}{6}=114\\\\\frac{544+x}{6}=114\\\\544+x=114*6\\\\544+x=684\\\\x=684-544\\\\x=140\\$

6 0

3 years ago

Help please will mark brainliest

stealth61 [152]

Answer:

-7

Step-by-step explanation:

7 0

3 years ago