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3 years ago

71 ×10 ^ 3 Scientific Notation

Mathematics

1 answer:

kap26 [50]3 years ago

7 0

Answer:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 1010. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

7.1×1047.1×104

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Two trains leave towns 1370 kilometers apart at the same time and travel toward each other. One train travels 18 km/h faster tha

inna [77]

Answer:

you have to divide the kilometers by the first train km/h and you should get the rate of each train

Step-by-step explanation:

hope it helps

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3 years ago

What is the description of one-hundredth of 36?

mafiozo [28]

One – hundredth is fraction that can also be written in decimal form. The fraction form is 1/00, while the decimal form is 0.01. so the description of the one hundredth of 36 can be solved by multiplying it by 0.01

36 x 0.01 = 0.36

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3 years ago

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on the coordinate plane, what is the length of the line segment that connects points at (5, 4) and (−3, −1) ? Enter your answer

gtnhenbr [62]

Distance between points
D= $\sqrt{(y2-y2)^2+(x2-x1)^2}$

points are (5, 4) and (−3, −1)

D=√(-1-4)^2+(-3-5)^2
D=√25+64
D=√89
D=9.433 units

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4 years ago

◆ Quadratic Equations ◆ Please help !

Mila [183]

I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

$\sf ax^2+(1-a(b+c))x+abc-d)$

$\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))$

Simplify into standard form:

$\sf x^2+(1-1(5))x+6-4$

$\sf x^2+(1-5)x+2$

$\sf x^2-4x+2$

Use the quadratic formula to solve:

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

For functions in the form of $\sf ax^2+bx+c$ . So in this case:

a = 1
b = -4
c = 2

Plug them in:

$\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}$

Solve for 'x':

$\sf x=\dfrac{4\pm\sqrt{16-8}}{2}$

$\sf x=\dfrac{4\pm\sqrt{8}}{2}$

$\sf x\approx\dfrac{4\pm 2.83}{2}$

$\sf x\approx 0.59,3.41$

So the answer would be A.

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4 years ago

Round 958,622 to the nearest hundred

HACTEHA [7]

Answer:

958,600

Step-by-step explanation:

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3 years ago

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71 ×10 ^ 3 Scientific Notation​

71 ×10 ^ 3 Scientific Notation