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2 years ago

URGENT PLZ HELP ME!!!

Mathematics

1 answer:

hichkok12 [17]2 years ago

4 0

Answer:

You would click at (0,-7)

Step-by-step explanation:

Definition of the minimum point:

"The minimum value of a function is the place where the graph has a vertex at its lowest point. In the real world, you can use the minimum value of a quadratic function to determine minimum cost or area."

Although this is not a quadratic, it still has a minimum point.

The minimum point here would be at it's lowest point

The minimum/lowest point is (0,-7)

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A 60 room hotel is filled to capacity every night at a rate of $40 per room. The management wants to determine if a rate increa

Oxana [17]

Answer: to maximize profit the management must continue charging $40 per room because it will obtain a profit of $1,920 better than $1,870 if it rises the rate.

Step-by-step explanation:

Profit without the increase

60 (number of rooms) * $40 (rate per room) = $ 2,400

costs of day to service = 60 (rooms) * $8 (costs day to service)= $480

Total Profit = $2,400 - $480 = $1,920

Profit with the increase

55 (5 fewer than before) * 42 (rate with the increase) = $ 2,310

costs of day service 55 (rooms) * 8 ( costs day to service) = $440

Total Profit = $2,310 -$440 = $1,870

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3 years ago

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3 years ago

What is the area of yhe following circle?either an exact answer in terms of or use 3.14 for and enter your ansert as a decimal

Harman [31]

Answer and Step-by-step explanation:

If the radius is 5, then we can plug 5 into the area of a circle equation.

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2 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

Slope:

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

Slope:

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$