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Natali5045456 [20]
3 years ago
8

What is the surface area?

Mathematics
2 answers:
Alina [70]3 years ago
5 0

The top is 4ft by 2 ft, area = 4 * 2=8 square feet.

The back is 1 1/2 ft by 4 feet, area = 1.5 *4 = 6 square feet.

The bottom equals the top = 8 square feet.

The front equals the back = 6 square feet.

The left side is 1 1/2 ft by 2 ft = 2 * 1.5 = 3 square feet.

The right side equals the left side = 3 square feet.


Total area = 8 + 6 + 8 + 6 + 3 + 3 = 34 square feet


Katyanochek1 [597]3 years ago
3 0

Answer:

2. 34 ft squared

Step-by-step explanation:

The surface area for a rectangular prism is given by

A=2(wl+hl+hw)

w =1 1/2 = 1.5

l =2 ft

h = 4 ft

A = 2( 1.5 * 2 + 4*2 + 4*1.5)

  = 2( 3 + 8 + 6)

  = 2( 17)

  = 34 ft^2

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Answer:

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2) Use a larger sample size

Step-by-step explanation:

a. The given parameters for the estimation of sample size is given as follows;

The margin of error for the confidence interval, E = 4% = 0.04

The confidence level = 95%

The sample size formula for a proportion as obtained from an online source is given as follows;

n = \dfrac{Z^2 \times P \times (1 - P)}{E^2}

Where, P is the estimated proportions of the desired statistic, therefore, we have for a new study, P = 0.5;

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Therefore, we have;

n = \dfrac{1.96^2 \times 0.5 \times (1 - 0.5)}{0.04^2} = 600.25

Therefore, the number of people that should be in the pilot study in order to meet this goal at 95% confidence level is n = 600 people

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\hat p = \dfrac{x}{n}

Where;

x = The number of the statistic in the sample

n = The sample size

From the question, we have;

The number of potential car buyers, n = 600

The number of respondent in the sample that indicated that they would consider purchasing a hybrid, x = 376

Therefore, the point estimate, for the proportion of potential car buyers that would consider buying a hybrid vehicle, \hat p = 376/600 = 0.62\overline 6

c. The confidence interval for a proportion is given as follows

CI=\hat{p}\pm z\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

Therefore, we get;

CI=0.62 \overline 6\pm 1.96\times \sqrt{\dfrac{\hat{0.62 \overline 6}\cdot (1-\hat{0.62 \overline 6})}{600}}

C.I. ≈ 0.6267 ± 0.0387

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d. The margin of error is given by the following formula;

MOE_\gamma = z_\gamma  \times \sqrt{\dfrac{\sigma ^2}{n} }

Where;

MOE_\gamma = Margin of error at a given level of confidence

z_\gamma = z-score

σ = The standard deviation

n = The sample size

Therefore, the margin error can be reduced by the following two ways;

1) Reducing the confidence interval and therefore, the z-score

2) Increasing the sample size

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