The translation of the question given is
A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?
Answer:
y = 5
Step-by-step explanation:
Line 1 that passes through A (2,1) and B (6,3)
Slope (m1) = 3-1/6-2 = 2/4 = 1/2
y - 1 =
( x -2)
2y - 2 = x- 2
y = 
Line 2 passes through A (2,1) and (0,y)
slope (m2) =
Line 1 and Line 2 are perpendicular
m1*m2 = -1
*
= -1
y-1 = 4
y = 5
slope = -2
Equation of Line 2
Y-1 = -2(x-2)
y -1 = -2x +4
2x +y = 5
Answer:
The triangle is acute.
Step-by-step explanation:
This is because each side is less than 90 degrees which would make the angles acute which would make the whole triangle acute.
By the general application of cumulative property of addition :
x + y = y + x
For sure
Answer:
1/15p?
Step-by-step explanation:
you’re multiplying p by 1/15 if I understood the question right
Answer:
Ф=xπ, x={0,+∞}
Step-by-step explanation:
be 19cosФ=5cosФ+14 → 19cosФ-5cosФ-14 → 14cosФ-14=0 → cosФ=1
then, values for which cosФ=1 are Ф=0º=360º=720º........., but the values of Ф must be radians, so Ф=xπ, where x∈Z, not including the negative numbers,
x={0,1,2,3,....∞}
Note: π≅3.141592
when calculating the values, it must be done in radian mode