<u>Answer</u>
Incorrect
<u>Explanation</u>
Unpack the problem:
Let the distance round the track to be X.
Speed is the ratio of distance to time.
Robert run a distance of (1/2)x
Elaine run a distance of (3/4)x
Make a plan:
Finding the speed of each.
Compare their speeds to determine who ran faster than who.
Solution:
Robert's speed =(1/2)x/(5/6)
=1/2×6/5x
= (3/5)x
= 0.6x
Elaine's speed = (3/4)x/(9/10)
= (3/4)×(10/9)x
= (5/6)x
= 0.83333x
<em>Elaine ran faster than Robert. </em>
<u>Look back and explain:</u>
0.83333x > 0.6x
Elaine's speed is higher than Robert's speed.
This shows that Elaine ran faster than Robert.
Number of students that have rabbits = 43
Number of students that have birds = 40
43 - 40 = 3
Thus, 3 more students have rabbits that birds.
Hence, the answer is A.
Answer:
1.5
Step-by-step explanation:
Answer:
70. 0
71. -54
72. 12
73. 86
74. 59
Step-by-step explanation:
To evaluate an expression, substitute specific values for the variables and simplify using Order of Operations.
70. c-3d becomes

71.
becomes

72.
becomes

73.
becomes

74.
becomes

Given:
The function is

To find:
The asymptotes and zero of the function.
Solution:
We have,

For zeroes, f(x)=0.



Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.


Taking square root on both sides, we get


So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.