Answer:
(2.5, - 10 )
Step-by-step explanation:
given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( 
, 
)
here (x₁, y₁ ) = (- 16, - 12 ) and (x₂, y₂ ) = (21, - 8 ) , then
midpoint = ( 
, 
) = ( 
, 
) = (2.5, - 10 )
To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
I am orearte sure the correct answer is 280 please give me brainliest if u can
Okay
(Thanks for the points)
<h3>
Answer: C) 0</h3>
================================================
Explanation:
If points F and E are the midpoints of segment VU and segment ST respectively, then segment FE is the midsegment of the trapezoid. The midsegment is parallel to the bases, and the midsegment's length is found by adding up the bases VS and UT, then dividing by 2.
(VS + UT)/2 = FE
(29 + x+17)/2 = 23 ... plug in given info; isolate x
(x+46)/2 = 23
x+46 = 23*2 ... multiply both sides by 2
x+46 = 46
x = 46-46 ... subtract 46 from both sides
<h3>
x = 0</h3>
