Hey there,
The whole number(or mixed fraction) would be: 1 2/3
The improper fraction would be: 5/3
:)
Use the information to write the dimensions of each rectangle in terms of w, the width of the 1st one.
1st rectangle;
l = 2w
w = 2
2nd rectangle:
w = w
l = 2w + 4
If the area of the 2nd rectangle is 70 square meters, you will use the area formula to write an equation that you will solve using the factoring.
A = lw
70 = w(2w + 4)
70 = 2w^2 + 4w
0 = 2w^2 + 4w -70
0 = 2 (w^2 +2w - 35)
0 = 2 (w + 7) (w - 5)
To get zero, the width would need to be -7 or 5. Because it is a distance, it has to be 5 meters.
The width of both rectangles is 5 meters.
Graph the line using the slope and y-intercept, or two points.
(Slope: 4)
Answer:
A) The value of a is <u>29</u>.
B) The value of b is <u>greater than 29</u>.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,

We have to solve for a.

By using addition property of equality, we will add both side by 9;

Hence the value of a is <u>29</u>.
Solving for Part B.
Given,

We have to solve for b.

By using addition property of inequality, we will add both side by 9;

Hence the value of b is <u>greater than 29</u>.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Here's how to rewrite cos^4x tan^2x in the first power of cosine.
See the attached image.
First step, find the trigonometric identity of tan^2x.
Then simply everything until you only get cos x.
Remove all the exponents. Simplify.