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Paraphin [41]
2 years ago
6

Which two of the following have the same value as 50.96? Choose 2 answers:

Mathematics
1 answer:
Firdavs [7]2 years ago
8 0

Answer:

A and C

Step-by-step explanation:

A: 5 tens = 50

9 tenths = 0.9

6 hundreths = 0.06

= 50.96

C: 5*10 = 50 + 9 * 1/10 = 0.9 + 6 * 1/100 = 50.96

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One eighth of the class graduated with an A average, 1/2 got a B, and the rest of the class had a C average. In a class of 800,
pogonyaev
I believe the answer would be 300. One eighth of the class would be 100 and 1/2 of the class would be 400. 800-(400+100)=300. Hope this helped!
8 0
3 years ago
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Point R(5,-3) and point N(9,-4) are on line k. What is the slope of the line passing through these points?
Aleks04 [339]
The slope of a line, denoted "m" is:

m=(y2-y1)/(x2-x1), where (x1,y1) and (x2,y2) are any two points on the line.

m=(-4--3)/(9-5)

m=-1/4

So the slope is negative one quarter.
8 0
3 years ago
Y is between points p and b. pt= 15 and tb = 10. what is pb
Kruka [31]
PT = 15, and TB = 10 

Take the 15 from PT, and add the 10 from TB. Which equals 25. 

PB = 25 

So, 25 is your answer. 

Hope this helps! ☺
4 0
3 years ago
3) When mixing a paint color, you need to use 2 gallons of white and 3 gallons of blue. How many gallons of
elixir [45]

Answer:

I think the answer is 25

Step-by-step explanation:

So, if you add 2 and 3, you get 5.

Multiply 5 by 10 to get 50

Divide 50 by 2 to get 25

So, you'll need 25 gallons of paint.

Hope this helped!

(Please mark as Brainliest <3)

6 0
2 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
3 years ago
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