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Nostrana [21]
3 years ago
14

The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the

car traveling in miles per hour?
Mathematics
1 answer:
Mumz [18]3 years ago
4 0
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad 
\begin{cases}
v=\textit{linear velocity}\\
r=radius\\
w=\textit{angular velocity}\\
----------\\
r=18in\\
w=1302\frac{\pi }{min}
\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}
\\\\\\
v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
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inside each set and subsets .write at least 5 example of each kind of number. integers , whole ,rational ,natural ,irrational​
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Answer:

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Then 5 examples of integers can be:

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Then 5 examples are:

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A circle has a radius of 6. An arc in this circle has a central angle of 330
sashaice [31]

Answer: Arc\ lenght\approx34.55\ units

Step-by-step explanation:

<h3> The complete exercise is: " A circle has a radius of 6. An arc in this circle has a central angle of 330 degrees. What is the arc length?"</h3><h3></h3>

To solve this exercise you need to use the following formula to find the Arc lenght:

Arc\ lenght=2\pi r(\frac{C}{360})

Where "C" is the central angle of the arc (in degrees) and "r" is the radius.

In this case, after analize the information given in the exercise, you can identify that the radius and the central angle in degrees, are:

r=6\ units\\\\C=330

Therefore, knowing these values, you can substitute them into the formula:

Arc\ lenght=2\pi (6\ units)(\frac{330}{360})

And finally,you must evaluate in order to find the Arc lenght.

You get that this is:

Arc\ lenght=2\pi (6\ units)(\frac{11}{12})\\\\Arc\ lenght=11\pi \ units\\\\Arc\ lenght\approx34.55\ units

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