<span>Simplifying
2x + 18y = 36
Solving
2x + 18y = 36
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-18y' to each side of the equation.
2x + 18y + -18y = 36 + -18y
Combine like terms: 18y + -18y = 0
2x + 0 = 36 + -18y
2x = 36 + -18y
Divide each side by '2'.
x = 18 + -9y
Simplifying
x = 18 + -9y</span>
The correct option that shows the population of the research carried out by Matthew is;
<u><em>Option D; all the students attending the college</em></u>
<u><em></em></u>
- We are told that Matthew wants to estimate the mean height of students attending his college.
- Now, let us say the total number of students in his college is x. If he decides to select 100 students randomly to record their height, it means this 100 students is a sample out of the total number of students which is x that is the population.
In conclusion, we can say that the population of this research by Matthew is the total number of students that attend the college.
Read more at; brainly.com/question/6028584
Answer:
the image shows reduction
Step-by-step explanation:
the scale chosen is 1.7
Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8
b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4
Step-by-step explanation:
Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40
a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8
There are one in hundred million chances that the draw numbers are precisely the chosen ones.
b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)
8×32
P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.
There are approximately 300,000 chances that 7 of the players numbers are chosen
c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.
P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]
P(at least 6 players numbers are drawn) = 1.84×10^-4.
There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.
It’s either A or B but I would choose B as the correct answer
