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joja [24]
3 years ago
11

Help me and be brainiest

Mathematics
1 answer:
Bingel [31]3 years ago
8 0

Answer:

4) C 3/4

5) Not sure


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)<br> 1.What is the additive of 3/8
tekilochka [14]

Answer:

3

Step-by-step explanation:

3 + (-8) - (-8)

= 3 - 8 + 8

= 3

6 0
3 years ago
Name the two planes that intersect at BD
ollegr [7]
The answer was BFC????????
4 0
4 years ago
I need to know what the ansswer is to this we are doing pemdas
mamaluj [8]

Answer:

18

Step-by-step explanation:

10-4+6(4-2)

10-4+6(2)

10-4+12

6+12

=18

8 0
3 years ago
Givem the geometric sequence where à1=2 and the common ratio is 4, what is domain for N
Dmitry_Shevchenko [17]

The domain for N is All integers where n ≥ 1

<u>Solution:</u>

According to statement a1 = 2 and r = 4. This shows that r is greater than 1.

If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.

If starting value is 2, if we put n=0, then we get 2, but if we put a negative value than we would get a number which is not a part of our sequence.

Thus the domain of n is All integers where n greater than or equal to 1

3 0
4 years ago
Gress<br> Solve the equation by completing the square.<br> x^2+6x + 11 =0
Mrrafil [7]

Answer:

x = -3±i sqrt(2)

Step-by-step explanation:

x^2+6x + 11 =0

Subtract 11 from each side

x^2+6x + 11-11 =0-11

x^2+6x =-11

Take the coefficient of the x terms

6

Divide by 2

6/2 =3

Square it

3^2 =9

Add it to each side

x^2+6x + 9 =-11+9

x^2 + 6x+9 = -2

The left hand side becomes (x+ (6/2) )^2

(x+3)^2 = -2

Take the square root of each side

sqrt((x+3)^2) = ±sqrt(-2)

x+3 = ±sqrt(-2)

x+3= ±i sqrt(2)

Subtract 3 from each side

x+3-3 = -3±i sqrt(2)

x = -3±i sqrt(2)

3 0
4 years ago
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