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2 years ago

PLEASE HELP ASAP!!!

Mathematics

2 answers:

valentina_108 [34]2 years ago

7 0

Answer with Step-by-step explanation:

For the Pythagorean triples, the square of largest number must be equal to the sum of squares of remaining two numbers.

1,2,5

5²=25

1²+2²=5

25≠5

Hence, it is not a Pythagorean triple.

6,8,14

14²=196

6²+8²=100

100≠196

Hence, it is not a Pythagorean triple.

8,15,17

17²=289

8²+15²=289

Hence, it is a Pythagorean triple

10,24,26

26²=676

10²+24²=676

Hence, it is Pythagorean triple

15,20,30

30²=900

15²+20²=625

900≠625

Hence, it is not a Pythagorean triple

28,45,53

53²=2809

28²+45²=2809

Hence, it is a Pythagorean triple

aivan3 [116]2 years ago

4 0

8,15,17 is one, 10,24,26 is one, and 28,45,53 is one

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Lapatulllka [165]

Measure of ∠C = 77°

And, Sides of triangles are;

a = 0.95

b = 0.566

c = 0.99

What is Sine rule of triangle?

By the definition of sine rule,

sin A / a = sin B / b = sin C / c

Where, a, b, c are sides of a triangle.

Given that;

Measure of ∠A = 27°

Measure of ∠B = 76°

Since, Sum of all angles of triangle = 180°

Hence,

∠A + ∠B + ∠C = 180°

27° + 76° + ∠C = 180°

∠C = 180° - 103°

∠C = 77°

So, Measure of ∠C = 77°

Since, By the definition of sine rule,

sin A / a = sin B / b = sin C / c

Since, sin A = sin 27° = 0.95

sin B = sin 76° = 0.566

sin C = sin 77° = 0.99

Hence,

0.95 / a = 0.566 / b = 0.99 / c = 1 / k

Taking terms as;

0.95 / a = 1 / k

a = 0.95 k

And, 0.566 / b = 1 / k

b = 0.566 k

And, 0.99 / c = 1 / k

c = 0.99 k

Hence, Sides of triangles are;

a : b : c = 0.95 k : 0.566 k : 0.99 k

a : b : c = 0.95 : 0.566 : 0.99

Thus, Measure of ∠C = 77°

And, Sides of triangles are;

a = 0.95

b = 0.566

c = 0.99

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PLEASE HELP ASAP!! Write a polynomial f(x) that satisfies the following conditions. Polynomial of lowest degree with zeros of -4

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Answer:

See below.

Step-by-step explanation:

So, we have the zeros -4 with a multiplicity of 1, zeros 2 with a multiplicity of 3, and f(0)=64.

Recall that if something is a zero, then the equation must contain (x - n), where n is that something. In other words, for a polynomial with a zero of -4 with a multiplicity of 1, then (x+4)^1 must be a factor.

Therefore, (x-2)^3 (multiplicity of 3) must also be a factor.

Lastly, f(0)=64 tells that when x=0, f(x)=64. Don't simply add 64 (like what I did, horribly wrong). Instead, to keep the zeros constant, we need to multiply like this:

In other words, we will have:

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