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3 years ago

Can someone please help me?

Mathematics

1 answer:

EleoNora [17]3 years ago

3 0

This will go -7/2,-2.1, square root of 9, 3.5,last will be square root of 5

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Perron years is 24 ounces of milk in a recipe how many cups in 24 ounces

Anon25 [30]

Answer:

3 cups

Step-by-step explanation:

1 cup is 8 ounces

5 0

3 years ago

PLEASE HELP ME I NEED IT RN

lapo4ka [179]

Answer:

(47) c. given

(48) b. definition of complementary

(49) a, m<2 = m<3

(50) d. definition of congruent angles

Step-by-step explanation:

From the given question, the proof can be completed as;

Statement Reason

1. <2 and < 1 are complementary (47) c. given

<3 and <1 are complementary

2. m<2 + m<1 = $90^{o}$ (48) b. definition of complementary angles

m<3 + m<1 = $90^{o}$

3. m<2 + m<1 = m<3 + m<1 3. Substitution property

4. (49) a, m<2 = m<3 4. Subtraction property

5. <2 ≅ <3 (50) d. definition of congruent angles

Therefore,

(47) c. given

(48) b. definition of complementary

(49) a, m<2 = m<3

(50) d. definition of congruent angles

5 0

3 years ago

5/8 as a decimal and a percentage

Usimov [2.4K]

Answer:

5/8 as decimal is 0.625 and 62.5 percent

Step-by-step explanation:

Multiply 5 by 12.5 then divide by 100 and once you get the decimal multiply by 100.

4 0

2 years ago

In a triangle XYZ, AB is a midsegment. Find the length of AB.

hammer [34]

Answer:

Option A. $AB=25\ units$

Step-by-step explanation:

step 1

Find the value of x

we know that

If AB is a mid-segment, then AB is parallel to YZ

Triangles AXB and YXZ are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

$\frac{YZ}{AB}=\frac{YX}{AX}$

we have that

$AB=\frac{1}{2}YZ$ ----> by Midpoint Theorem

$YZ=2AB$

substitute the given values in the expression above

$\frac{2AB}{AB}=\frac{22+2x+2}{2x+2}$

solve for x

$2=\frac{24+2x}{2x+2}$

Multiply by (2x+2) both sides

$4x+4=2x+24$

Group terms

$4x-2x=24-4$

$2x=20$

$x=10$

step 2

Find the length of AB

$AB=3x-5$

substitute the value of x

$AB=3(10)-5=25\ units$

3 0

4 years ago

Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0

3 years ago