To get the number of members between 15 years and 30 years we proceed as follows:
z=(x-μ)/σ
where:
mean,μ=23
standard deviation, σ=4 years
thus
P(15<x<31)
when x=15
P(x<15)
z=(15-23)/4
z=-2
thus
P(x<15)=P(z<-2)=0.0228
when x=31
z=(31-23)/4
z=2
thus
P(x<31)=P(z<2)=0.9772
Hence:
P(15<x<31)=0.9544
hence the number of members between that age was:
0.9544×300
=286.32 people
~285 People
Answer: 285 people
        
             
        
        
        
Answer:
the answer for your problem is -3/2 by my calculations. Just had a lesson on quadratic equations in class 
 
        
             
        
        
        
Answer:
60th caller.
the 12th caller would hit a number divisible by 20 at 60.
12,24,35,48,60
 
        
             
        
        
        
He earns 23 000 000 per 80 games for 48min
Per game he earns 

If he earns 782 500 per game he earns 5 989,5833 per minute

If he played 2/3 of the time he played 32min which means he earned... 

So he trained 35hours for a 48min match
Together that is 35.8hours
But I dont think this really matters here you just have to multiply 24453.125 with 60
And you get his hourly salary which is 1 467 187.5
 
        
        
        
Just as you would do it with any other number.
Write out some of it, then move the decimal point 3 places this way <=== .
Some of pi :                   3.14159  
Divide by 1,000 :     0.00314159