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worty [1.4K]
3 years ago
8

The product of -3 and a number is less than or equal to -15

Mathematics
1 answer:
Alex777 [14]3 years ago
8 0
It can be 5, because 5 times -3 = -15
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5 Points
LekaFEV [45]

Answer:

1043.43

Step-by-step explanation:

6 0
3 years ago
Simplify the following expression please solve correctly<br> −12^12 ^2 / 3^ 5 ^5
nikdorinn [45]

The simplified expression is -\frac{48}{x^{3} y^{3}}

Explanation:

The given expression is \frac{-12x^{2}12y^{2}  }{3x^{5} y^{5} }

Let us simplify the expression.

Multiplying the numbers in the numerator, we have,

\frac{-144 x^{2} y^{2}}{3 x^{5} y^{5}}

Dividing the term 144 by 3, which results in 48.

Thus, we have,

\frac{-48 x^{2} y^{2}}{x^{5} y^{5}}

Applying the fraction rule \frac{-a}{b}=-\frac{a}{b} , we get,

-\frac{48 x^{2} y^{2}}{x^{5} y^{5}}

Applying the exponent rule \frac{x^{a}}{x^{b}}=\frac{1}{x^{b-a}}, we have,

-\frac{48}{x^{3} y^{3}}

Thus, the simplified expression is -\frac{48}{x^{3} y^{3}}

7 0
3 years ago
What is the GCF of<br> 1/3 and 2/5
Semenov [28]

Answer:

The GFC of 1/3 and 2/5 is <em>1</em>

7 0
3 years ago
Read 2 more answers
Y=13(2)^x<br> is grow , decay or neither
leva [86]

Answer:

Growth

Step-by-step explanation:

Since 2 is a number greater than 1, it is exponential growth

If it the number in the parentheses were 1, it would be neither

If it were a fraction less than 1, it would be decay

7 0
3 years ago
Read 2 more answers
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Lerok [7]

Answer:

Q1 - D. f(x) = x^4-9x^2-50x-150

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Q14 - A. 7x+6+4x^{2}

Step-by-step explanation:

Question 1:

We know that rational roots always occurs in pairs. So, the zeros of the function will be 5, -3, -1+3i, -1-3i

So, the factored form is (x-5)(x+3)(x+1-3i)(x+1+3i)=0

i.e. (x^2-2x-15)(x+1-3i)(x+1+3i)=0

i.e. (x^3-x^2-3ix^2-17x+6ix-15+45i)(x+1+3i)=0

i.e. x^4-9x^2-50x-150=0

Hence, the polynomial function is f(x)=x^4-9x^2-50x-150.

Question 13:  

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if \frac{p}{q} is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, \frac{p}{q} is a zero of x^3-7x^2+9x-24=0. Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of \frac{p}{q} are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = 4x^{2}

Then, (f+g)(x) = f(x) + g(x) =  7x + 6 + 4x^{2}

So, (f+g)(x) = 7x+6+4x^{2}

6 0
4 years ago
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