Specify 3 fractions with different denominators that have an LCD of 24

1 answer:

7 0

1/3, 1/4, 1/8 The answer given is not the only possible answer. You need to come up with 3 different fractions so that the LCD (least common denominator) So first, determine the prime factors of 24. 24 = 2 * 2 * 2 * 3 Now you want some denominators that will need all of those prime factors. For the above list of 3, 4, 8, only the 3 and 8 are important, since one of them uses the prime factor of 3 and the other uses 3 prime factors of 2, so the LCD for those 2 numbers is 24. The 3rd denominator could be almost anything that uses some combination of prime factors 2,2,2,3 such as 1/2, 1/4, 1/6, 1/12, etc. I just happened to pick 1/4. The only real restriction is that none of the denominators can use any extra prime factors. If they did. then the resulting LCD would not be equal to 24.

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Answer the following Question

anastassius [24]

Answer:

a)$15.95

b) 8kg

Step-by-step explanation:

a)Approach this question by finding how much does it cost for 1g

So,

$2.1/50=$0.042per gram

then, multiple 380 to get the cost of sweets for 380 g

$0.042/gram*380gram=$15.96(Note: the gram cancel out each other)

Which is $15.95 as the question requested

b)This question stated that 3/4 of the metal has 15 kg

So, in order to find the total mass of metal we invert the 3/4 fraction

e.g 4/3*15=20kg

now we have the total mass we can find the mass for 2/5 of the metal

2/5*20kg=8kg

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omeli [17]

If 30% of his collection is 12 cars, then we can use the fraction

30/12=100/x

x=40

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3 years ago

Which number is a prime number? 161. 151. 141. 171.

Scorpion4ik [409]

I think the answer is 151.

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3 years ago

Please answer...................................

vekshin1

Answer:

for the first one- 1/8 0.25= decimal and percent=12.5%

Second 8 boxes and shade in 6 0.75=decimal 75%

Step-by-step explanation:

8 0

3 years ago

If p(a|b) = 0.35, p(b) = 0.75 and p(a) = 0.44 are the events a and b independent ?

MatroZZZ [7]

Hello :
note 1 :
p(A|B) = p(A∩B)/ p(B)

note 2 :
 A and B independent: p(A∩B) = p(A)×p(B)
calculate : p(A∩B)
p(A∩B) = p(A|B)×p(B)
p(A∩B) = 0.35 ×0.75 = 0.2625
but : p(A)×p(B) = 0.44×0.75 = 0.33
conclusion :
the events A and B are not independent ?

6 0

3 years ago