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Karo-lina-s [1.5K]
3 years ago
15

Complete the statements about calculating mean using the data set: 4, 6, 1, 9, 12, 3, 11,2

Mathematics
1 answer:
ryzh [129]3 years ago
8 0

Answer: 6

<u>Order the Numbers</u>

Before: 4, 6, 1, 9, 12, 3, 11, 2

After: 1, 2, 3, 4, 6, 9, 11, 12

<u>Add</u>

1+2+3+4+6+9+11+12=48

Sum: 48

<u>Divide</u>

48÷8=6

Mean: 6

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What is the answer to this problem 6(1-5m)
Ivahew [28]
Apply the distributive property.<span>6⋅1+6<span>(−5m<span>)

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An aptitude test is designed to measure leadership abilities of the test subjects. Suppose that the scores on the test are norma
Komok [63]

Using the normal distribution, it is found that 0.0329 = 3.29% of the population are considered to be potential leaders.

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 550, hence \mu = 550.
  • The standard deviation is of 125, hence \sigma = 125.

The proportion of the population considered to be potential leaders is <u>1 subtracted by the p-value of Z when X = 780</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{780 - 550}{125}

Z = 1.84

Z = 1.84 has a p-value of 0.9671.

1 - 0.9671 = 0.0329

0.0329 = 3.29% of the population are considered to be potential leaders.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

8 0
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