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gulaghasi [49]
3 years ago
9

Math help me))))))))please

Mathematics
2 answers:
olasank [31]3 years ago
6 0
X^2/(x- 9 = 81/(x - 9)
This is the equation for which you want the solution.
Multiplying both sides of the equation by (x - 9) we get
x^2(x - 9)/(x - 9) = 81(x - 9)/(x - 9)
So the (x - 9) goes out from both the denominator and the numerator and then the simplified equation becomes
x^2 = 81
x ^2 = (9)^2
x = 9
So the value of the unknown variable x comes out to be 9.
svp [43]3 years ago
5 0

Multiply each side of the equation by  (x - 9) .
Then the equation says:
                                               x²  =  81 .

Take the square root of each side:

                                               x  =  +9
                                               x  =  -9 .

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PLS HELP ME
eimsori [14]

Answer:

5.5

Step-by-step explanation:

2,3,3,4,5,7,8,8,8,10,10,12

The mean of this data is 7.5.  So what you are trying to figure out is the mean between 2 and 7.  Since that is 3 and 4 it would be 3.5.  So 3.5 is the Q1.  Now you have to figure out the mean between 8 and 12.  That is 9.  This is Q3.  You have to subtract 9-3.5 and that is the interquartile range. So 5.5 is the answer.  I hope that made sense.

6 0
2 years ago
40. What is the system of inequalities associated with the following graph?
SpyIntel [72]

Answer:

The bottom answer

Step-by-step explanation:

4 0
3 years ago
Wanni cycled 6 km from her house to the school at a uniform speed, v km/h. If she increased her speed
Karolina [17]

Answer:

The quadratic equation in terms of v is   v² + 2 v + 180 = 0

Step-by-step explanation:

Given as :

The distance between house to the school = d = 6 km

The uniform speed = v km/h

So, Time = \dfrac{\textrm Distance}{\textrm speed}

or, t = \dfrac{\textrm d}{\textrm v}

Or, t = \dfrac{\textrm 6}{\textrm v}

<u>Now, Again</u>

The speed is increase by 2 km/h

i.e speed = (v + 2) km/h

So, Time taken = t' = (t - \dfrac{4}{60})hours

i.e t' =  (t - \dfrac{1}{15})hours

Now, Time = \dfrac{\textrm Distance}{\textrm speed}

So, (t - \dfrac{1}{15}) = \dfrac{\textrm d}{\textrm v}

Or,  (t - \dfrac{1}{15}) = \dfrac{\textrm 6}{\textrm (v + 2)}

Or , \dfrac{\textrm 6}{\textrm v} -  \dfrac{1}{15} = \dfrac{\textrm 6}{\textrm (v + 2)}

Or , \dfrac{\textrm 90 - v}{\textrm 15 v} = \dfrac{\textrm 6}{\textrm v + 2}

Or, (90 - v) × (v + 2) = 6 × 15 v

Or, 90 v - 180 - v² - 2 v = 90 v

Or,  v² + 2 v + 180 = 90 v - 90 v

Or,  v² + 2 v + 180 = 0

So, The quadratic equation in terms of v

v² + 2 v + 180 = 0

Hence The quadratic equation in terms of v is   v² + 2 v + 180 = 0   Answer

3 0
3 years ago
Enter a range if values for x.
Blizzard [7]

Answer:

See the attachment photo!

3 0
2 years ago
Answer the questions
Mnenie [13.5K]

Answer:

c) x= 15

d) x= 5

Step-by-step explanation:

c)4x + 5+ 7x +10=180

solve it like usually

for d) 3x + 15+12x=90

8 0
3 years ago
Read 2 more answers
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