Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.
Answer:
Step-by-step explanation:
Given
Required
Probability of two people having dog
First, we have to convert the given parameter to decimal
Let P(Dogs) represent the required probability;
This is calculated as thus;
<em>P(Dogs) = Probability of first person having a dog * Probability of second person having a dog</em>
<em />
<em>Hence, the probability of 2 people having a dog is </em><em />
Answer: 9 Apples
Step-by-step explanation:
Given the following :
Total number of bags = 12
Mean of the distribution(m) = 8
Number of apples (x):
6 - - - - 7 - - - - 8 - - - - 9 - - - - 10
Frequency (f) :
1 - - - - 4 - - - - 2 - - - - 3 - - - - 1
Therefore :
Let number of apples in the 12th bag = y
Frequency of 12th bag : (12 - 11) = 1
Mean of distribution(m) :
Sum of ( f * x) / sum of f
Sum of (f * x) = (6*1)+(7*4)+(8*2)+(9*3)+(10*1)+(y*1)
Sum of (f * x) = (6+28+16+27+10+y) = 87 + y
Sum of f = 12
From :
m = Sum of ( f * x) / sum of f
8 = (87 + y) / 12
87 + y = 12 * 8
87 + y = 96
y = 96 - 87
y = 9
Number of apples in 12th bag is 9 apples
<span>I, only. The first situation is a linear function, growing the same amount every day. (Constant slope) The other two are exponential functions with the amount changing from interval to interval. Even if the percentage remains the same.</span>
