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Rudik [331]
3 years ago
8

Use the unit circle to find the value of each trigonometric function at the angle indicated

Mathematics
2 answers:
Elan Coil [88]3 years ago
8 0
0
-1
-inf
1
0
0

repectively
Mars2501 [29]3 years ago
5 0

Answer:

Step-by-step explanation:

We have to find the values of the given trigonometric ratios at the angle indicated. Thus,

(A) The given trigonometric function is:

cos270^{\circ}

Since, the function lies in Quadrant III, therefore the value of the function will be negative.

Also, cos270^{\circ}=-(0)=0

(B) The given trigonometric function is:

sin270^{\circ}

Since, the function lies in Quadrant III, therefore the value of the function will be negative.

Also, sin270^{\circ}=-1

(C) The given trigonometric function is:

tan270^{\circ}

Since, the function lies in Quadrant III, therefore the value of the function will be negative.

Also, tan270^{\circ}=undefined

(D) The given function is:

cos0^{\circ}

Since, the function lies in Quadrant I, therefore the value of the function will be positive.

Also,  cos0^{\circ}=1

(E) The given function is:

sin0^{\circ}

Since, the function lies in Quadrant I, therefore the value of the function will be positive.

Also,  sin0^{\circ}=0

(F) The given function is:

tan0^{\circ}

Since, the function lies in Quadrant I, therefore the value of the function will be positive.

Also,  tan0^{\circ}=0

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\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

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Step-by-step explanation:

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