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2 years ago

9 less than the sum of x and 5

Mathematics

1 answer:

saw5 [17]2 years ago

7 0

Answer:

Given the statement:

9 less than the sum of x and 5

"Sum of x and 5" means $x+5$

" $\text{less than}$ " means subtract

then;

the statement 9 less than the sum of x and 5 becomes;

⇒ $(x+5) - 9$

⇒ $x+5-9 = x-4$

Therefore, the expression for the given statement is $(x+5) - 9$

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Grace bought a property valued at $200,00.00 and 20% down and a mortgage amortized over 10 years. She makes equal payments due a

BlackZzzverrR [31]

Answer:

Size of each monthly payment = $161.69 per month

Step-by-step explanation:

Given:

Value of property = $20,000

Downpayment = 20%

Number of payment = 12 x 10 = 120

Interest rate = 4% = 4% / 12 = 0.33 %

Computation:

Loan balance = 20,000 - 20%

Loan balance = $16,000

A] Size of each monthly payment [In Excel]

Size of each monthly payment = PMT(0.33%,120,16000,0)

Size of each monthly payment = $161.69 per month

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2 years ago

Simplify 4 to the 7th over 5 squared all raised to the 3rd power.

Radda [10]

First write out your original equation.
${(\frac{ {4}^{7} }{ {5}^{2} } ) }^{3}$
Then use the law of exponents(power of a power) to simplify.
$\frac{ {4}^{21} }{ {5}^{6} }$
(Multiply the numerator and denominator exponents by the outside power.)

The answer is 4 to the 21st over 5 to the 6th.

6 0

2 years ago

What is the area of this parallelogram? in or in2

Ket [755]

Answer:

A=30 in

Step-by-step explanation:

Solution

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2 years ago

Read 2 more answers

The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.

Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let $\mu$ = population mean score

So, Null Hypothesis, $H_0$ : $\mu \leq$ 29.5 {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, $H_A$ : $\mu$ > 29.5 {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean MCAT score = 32.2

s = sample standard deviation = 4.2

n = sample of students = 40

So, the test statistics = $\frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }$ ~ $t_3_9$

= 4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0

3 years ago

A graph of a system of two equations is shown. PLEASE HELPP!!!!!

ale4655 [162]

Answer:

From the graph

$x=1$

$y=0$

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hope it helps...

have a great day

4 0

2 years ago