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kodGreya [7K]
3 years ago
6

Does 3.2 - 4d=2.3d+3 no solution or identity

Mathematics
2 answers:
Fynjy0 [20]3 years ago
7 0
D=0.04286 is the answer
Setler79 [48]3 years ago
4 0
This equation does have a solution and it is 0.03174603
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I need help on this parallelograms math problem.
Andrews [41]

w=37

2w+w+69= 180 knowing that all triangles add up to 180 form an equation

3w+69=180 combine like terms and subtract 69 from both sides

3w=111 divide by 3 from both sides

w=37

5 0
3 years ago
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Please help me I do not get this!! Thanks
Solnce55 [7]
The answer is C. Hope you get it!
7 0
3 years ago
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What is the answer to my question
Vedmedyk [2.9K]
672 cm³
Step-by-step explanation:
10x7x9=630
2x3x7=42
630+42=672
5 0
3 years ago
What is the square root of 4
ipn [44]

Answer: 2

Step-by-step explanation:

square root means that you divide a number by the prime factorization, in this case you take 4 and divide it by the number that is multiplied twice to get that number, ex. 3*3 or 2*2

6 0
3 years ago
Three numbers form a geometric progression. If the second term is increased by 2, the progression will become arithmetic and if,
Evgesh-ka [11]

In this exercise we have to use the knowledge of geometric progression to find three specific numbers, in this way we can say that these numbers correspond to;

0.16\\ -0.64\\ 2.56

Then using the formula of the geometric progression we find that:

a_1*r = a_2\\a_2*r = a_3 = a_1*r^2

now, the differences between the terms must be the same:

a1*r + 2 - a_1 = a_3 - (a_1*r + 2) = a_1*r^2 - (a_1*r + 2)\\a_1*r^2 - 2*a_1*r + a_1 - 4 = 0

and now, when we increase the third term by 9,so we have:

(a_1*r^2 + 9)/(a_1*r + 2) = (a_1*r + 2)/a_1\\(a_1^2*r^2 + 9*a_1)/(a_1*r + 2) = a_1*r + 2\\a_1^2*r^2 + 9*a_1 = (a_1*r + 2)^2 = a_1^2*r^2 + 4*a_1*r + 4\\4*a_1*r - 9*a_1 + 4 = 0\\9*a - 4 = 4*a_1*r\\r = (9*a_1 - 4)/(4*a_1)

Now we use that identity in the first equation :

a_1*(9*a_1 - 4)^2/(4×a_1)^2 - 2*a_1*(9*a_1 - 4)/(4*a_1) + a_1 - 4 = 0\\(81*a_1^2 - 72*a_1 + 16)/(16*a_1) - (9*a_1 - 4)/2 + a_1 - 4 = 0\\81*a_1^2 - 72*a_1 + 16 - 8*a_1*(9*a_1 - 4) + 16*a_1^2 - 64*a_1 = 0\\25a_1^2 - 104a_1 + 16 = 0

The general solution for a quadratic equation is

(-b + \sqrt{(b^2 - 4ac))/(2a)

We have that:

  • a = 25
  • b = -104
  • c = 16

so, put the numbers in the formula we find:

a_1=4 \\a_1=0.16

See more about geometric progress at brainly.com/question/14320920

5 0
2 years ago
Read 2 more answers
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