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galina1969 [7]
2 years ago
7

Help me please you guys. Been stuck on this one for an hour

Mathematics
1 answer:
nekit [7.7K]2 years ago
7 0
I think the answer is d hope this helps
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In a survey 9/25 students ride the bus and 19/50 walk to school. What fraction of students ride the bus or walk?
san4es73 [151]
Well since 19/50 can't be simplified you have to double 9/25 which is 18/50 so then add 18 + 19 = 37 So 18/50 + 19/50 = 37/50 so 37/50 of the students ride the bus or walk to school.
7 0
3 years ago
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Is x = −8 a solution of the equation 3(x + 1) = 3x + 3?
n200080 [17]

Answer:

Yes

Step-by-step explanation:

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You roll a fair 6-sided die.
Yuki888 [10]

Answer:

1/3

Step-by-step explanation:

7 0
3 years ago
What is two and two fourths plus one third
kkurt [141]

Answer:

2 5/6

Step-by-step explanation:

2 2/4 + 1/3

First, you have to make the bottoms of the fraction the same, by figuring out the lowest common denominator. In this case it would be 12. 4x3 = 12. 3x4 = 12.

Multiply the top number by the same number you multiplied the bottom by.

We multiplied the 4 by 3, so we would also multiply the 2 by 3 (which would be 6).

Do the same for the second fraction. 1x4 = 4.

Now we have 2 6/12 + 4/12. We add the top numbers together and we get 10/12.

Now we have to reduce the fractions. We can do this in this situation by just dividing the top and bottom numbers by 2.

2 5/6

8 0
3 years ago
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
2 years ago
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