Csc a - sin a = cos a cot a
1/sin a - sin a = cos a (cos a / sin a)
(1 - sin^2 a)/sin a = cos^2 a/sin a
cos^2 a/sin a = cos^2 a/sin a
Therefore, the given equation is an identity.
T=650mi(hr/50mi)=13 hr
t-1=12 hr
12=650/(50+v) multiply both sides by 50+v
600+12v=650 subtract 600 from both sides
12v=50 divide both sides by 12
v=25/6 mph
v≈4.17mph
We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2
the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14
</span>
Answer:
u = 16
Step-by-step explanation:
Given
u = 12
Multiply both sides by 4 to eliminate the fraction
3u = 48 ( divide both sides by 3 )
u = 16
There is no one ordered pair that makes the equation true, this is a line which has infinitely many ordered pairs that are true...
2x+y=11 subtract 2x from both sides and you have the line in slope intercept form..
y=11-2x
For any real given value of x, you will get one real unique corresponding value for y, resulting in infinitely many unique (x,y) values, points, or ordered pairs, satisfying the given equation.
I assume that you were given "choices" to pick from because of the above reality. So if any of your choices does not satisfy y=11-2x it is not an ordered pair satisfying the equation.
