Question

State whether the given measurements determine zero, one, or two triangles.

Answer 1

Let's apply the law of sine  to calculate angle C
sin(81)/26 =  sin(C)/28
0.1646 = sin(C)/28 and sin(C) =1.063. Sine sin(α) cannot be > than 1, so this triangle is invalid

Answer 2

Answer:

Step-by-step explanation:

Alright, lets get started.

Side b = 26

Side c = 28

Angle B = 81

Using sin law

$\frac{sinB}{b}=\frac{sinC}{c}$

$\frac{sin81}{26}=\frac{sinC}{28}$

$sinC= \frac{28sin81}{26}$

$sinC= \frac{28*0.98769}{26}=1.06$

We got sin C value 1.06 which is more than 1, that is not possible because its out of range for sin function.

It means triangle is not possible.

Hence Zero triangle.   :    Answer

Hpe it will help :)