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3 years ago

State whether the given measurements determine zero, one, or two triangles.

2 answers:

german3 years ago

6 0

Let's apply the law of sine to calculate angle C
sin(81)/26 = sin(C)/28
0.1646 = sin(C)/28 and sin(C) =1.063. Sine sin(α) cannot be > than 1, so this triangle is invalid

creativ13 [48]3 years ago

6 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Side b = 26

Side c = 28

Angle B = 81

Using sin law

$\frac{sinB}{b}=\frac{sinC}{c}$

$\frac{sin81}{26}=\frac{sinC}{28}$

$sinC= \frac{28sin81}{26}$

$sinC= \frac{28*0.98769}{26}=1.06$

We got sin C value 1.06 which is more than 1, that is not possible because its out of range for sin function.

It means triangle is not possible.

Hence Zero triangle. : Answer

Hpe it will help :)

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Solve <br>In 2x + In 2=0

irakobra [83]

Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Step-by-step explanation:

We need to solve: $ln(2x)+ln(2)=0$

Solving:

$ln(2x)+ln(2)=0$

Adding -ln(2) on both sides:

$ln(2x)+ln(2)-ln(2)=0-ln(2)$

$ln(2x)=-ln(2)$

Using logarithmic rule: if $log_a b =c\,\,then\,\, b=a^c$

So,

$2x=e^{-ln(2)}$

Simplifying:

$2x=(e^{ln(2)})^{-1}\\e^{ln(2)}=2\\2x=(2)^{-1}\\2x=\frac{1}{2} \\x=\frac{1}{2x2}\\x=\frac{1}{4}$

So, Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Keywords: Logarithms

Learn more about Logarithms at:

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4 0

4 years ago

In the triangle above, which angle is smallest in measure?

Setler79 [48]

Angle A because the opposite side is the smallest, the smallest side being 28.49.

8 0

3 years ago

Read 2 more answers

The line AB has midpoint (2,5).<br> A has coordinates (1, 2).<br> Find the coordinates of B.

Gekata [30.6K]

Answer:

$X_m = \frac{A_x +B_x}{2}= \frac{1+B_x}{2}= 2$

And we can solve for $B_x$ and we got:

$1+B_x = 4$

$B_x = 3$

$Y_m = \frac{A_y +B_y}{2}= \frac{2+B_y}{2}= 5$

And we can solve for $B_x$ and we got:

$2+B_y = 10$

$B_y = 8$

So then the coordinates for B are (3,8)

Step-by-step explanation:

For this case we know that the midpoint for the segment AB is (2,5)

And we know that the coordinates of A are (1,2)

We know that for a given segment the formulas in order to find the midpoint are given by:

$X_m = \frac{A_x +B_x}{2}= \frac{1+B_x}{2}= 2$

And we can solve for $B_x$ and we got:

$1+B_x = 4$

$B_x = 3$

$Y_m = \frac{A_y +B_y}{2}= \frac{2+B_y}{2}= 5$

And we can solve for $B_x$ and we got:

$2+B_y = 10$

$B_y = 8$

So then the coordinates for B are (3,8)

7 0

4 years ago

What is the value of x which proves that the runways are parallel? What is the measure of the larger angle?

makkiz [27]

Answer:

118°

Step-by-step explanation:

When two parallel lines are cut by a tranversal, then the exterior angles are supplimentary and the corresponding angles are congruent.

Therefore the angle above (15x - 17)° is also (5x + 17)° and the angle below (5x + 17)° is also (15x - 17)°.

Angles on a straight line adds up to 180°. So to know the measure of the larger angle we must both equations and equal it to 180° to find x in order to know the larger angle.

(5x + 17) + (15x - 17) = 180

5x + 15x + 17 - 17 = 180

20x = 180

20x/20 = 180/20

x = 9°

Nkw let's substitute x = 9 into the equations

5x + 17 =

5(9) + 17 =

= 62°

15x - 17 =

15(9) - 17 =

= 118°

Both equations should add up to be 180°.

Therefore the measure of the largest angle is 118°.

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3 years ago

PLEASE HELP! is slope = undefined the same as y = 0?

olchik [2.2K]

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3 years ago