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Diano4ka-milaya [45]
3 years ago
6

in Ryan's V. Class 50% of the students like the teacher if 15 of the students like the teacher how many students are in that cla

ss​
Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer: 30 students.

Step-by-step explanation: They are saying 50% of the class like the teacher. We know that 50% is half of the 100% so that mean only half of the students like the teacher. Is 15 students like the teacher it means that 15 are half of the students in the class. The other half should be another 15. So 15+15=30 or 15x2=30.

I hope I didn’t make it to confusing.

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The measure of an angles suppliment is 53° more than twice that of its compliment. find the angle.
Anettt [7]
(180-x)-2(90-x)= 53
Remember that complimentary angles add to 90 and supplementary angles add to 180.

180-x-180+2x=53
x=53

Final answer: The angle is 53 degrees.
3 0
2 years ago
Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

4 0
3 years ago
Can someone help me with this question please.
ozzi

Answer:

x=88° a=+3 b=4a-3

Step-by-step explanation:

as triangles ADE and BCE are congruent by sss axiom

so correponding angles are equal

i.e<AED = <BEC

and <DAE =90-60

=30°

so

62°+x+30°=180°

therefore x=88°

5 0
3 years ago
What can you weave into your game in order to make it easier to pinpoint a particular audience?
Viktor [21]

Answer:

B. A secret cheat

Step-by-step explanation:

Correct me if i am wrong

6 0
2 years ago
In the diagram below, line d is parallel to line c.
My name is Ann [436]

Answer:

85° = ∠x {corresponding angles}

∠x = ∠1 {vertically opp. angles}

And, ∠2 + 103° = 180° ( co-interior angles)

∠2 = 180° - 103°

∠2 = 77°

Now, m∠1 + m∠2 = 85° + 77°

= 162°

Hemce, option A. is the right answer.

6 0
2 years ago
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