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mars1129 [50]
1 year ago
11

Line WS is parallel to line KV. Line RT is perpendicular to line KV. Explain the relationship of line RT to line WS. Provide at

least one reason to support your answer
Mathematics
1 answer:
Gala2k [10]1 year ago
7 0

The product of the slope of the line RT and WS is equal to -1 if the line WS is parallel to line KV. Line RT is perpendicular to line KV.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have line WS is parallel to line KV. Line RT is perpendicular to line KV.

Let's suppose the slope for the line WS is m1, for the slope for the line KV is m2, and for the line RT is m3.

We know if the two lines are parallel, their slope will be the same mathematically,

m1 = m2

And if the two lines are perpendicular to each other, their product of the slope will be -1

Because the slope is given by:

\rm tan\theta = \dfrac{m_1-m_2}{1+m_1m_2}

If parallel, then tanθ = 0

\rm m_1 -m_2= 0\\m_1 =m_2

If perpendicular, then \rm tan\theta = \dfrac{1}{0}

\rm 1+m_1m_2 = 0\\m_1m_2 = -1

Thus, the product of the slope of the line RT and WS is equal to -1 if the line WS is parallel to line KV. Line RT is perpendicular to line KV.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

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Answer:

18 seconds

Step-by-step explanation:

according to the question

-16t²+5184=0 (0 because when the height is 0 the ball will hit the ground)

-16t²=-5184

t²=-5184/-16

t²=324

t=√324

t=18

8 0
3 years ago
A recent poll found that 35% of those surveyed are worried about aggressive drivers on the road. If three people are selected at
Ugo [173]

The probability that all three people surveyed is an independent probability and the calculated probability is 0.1225

The probability a surveyed driver is worried = 35%

  • P(worried) = 0.35

  • Number of people surveyed = 3

Since the probability of being worried is independent ;

  • Probability = P(A) × P(B) × P(C)

The probability that all 3 surveyed are worried :

  • P(worried) × P(worried) × P(worried)
  • (0.35 × 0.35 × 0.35) = 0.1225

Therefore, the probability that all three people surveyed are worried is : 0.1225

Learn more : brainly.com/question/18153040

5 0
2 years ago
A pair of bottlenose dolphins at an aquarium are fed 45 pounds of fish each day. The aquarium recently added another dolphin. Ho
Arte-miy333 [17]

Answer:

67.5 pound of fish are needed to feed 3 dolphins

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3 years ago
A phase modulator produces a maximum phase shift of 45 degrees. The modulation frequency range is 300 to 4000 Hz. What is the ma
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Answer:

Maximum frequency deviation is 2616.29509 Hz

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Max frequency deviation=2616.29509 Hz

8 0
3 years ago
Need help with AP CAL
anzhelika [568]

Answer: Choice C

\displaystyle \frac{1}{2}\left(1 - \frac{1}{e^2}\right)

============================================================

Explanation:

The graph is shown below. The base of the 3D solid is the blue region. It spans from x = 0 to x = 1. It's also above the x axis, and below the curve y = e^{-x}

Think of the blue region as the floor of this weirdly shaped 3D room.

We're told that the cross sections are perpendicular to the x axis and each cross section is a square. The side length of each square is e^{-x} where 0 < x < 1

Let's compute the area of each general cross section.

\text{area} = (\text{side})^2\\\\\text{area} = (e^{-x})^2\\\\\text{area} = e^{-2x}\\\\

We'll be integrating infinitely many of these infinitely thin square slabs to find the volume of the 3D shape. Think of it like stacking concrete blocks together, except the blocks are side by side (instead of on top of each other). Or you can think of it like a row of square books of varying sizes. The books are very very thin.

This is what we want to compute

\displaystyle \int_{0}^{1}e^{-2x}dx\\\\

Apply a u-substitution

u = -2x

du/dx = -2

du = -2dx

dx = du/(-2)

dx = -0.5du

Also, don't forget to change the limits of integration

  • If x = 0, then u = -2x = -2(0) = 0
  • If x = 1, then u = -2x = -2(1) = -2

This means,

\displaystyle \int_{0}^{1}e^{-2x}dx = \int_{0}^{-2}e^{u}(-0.5du) = 0.5\int_{-2}^{0}e^{u}du\\\\\\

I used the rule that \displaystyle \int_{a}^{b}f(x)dx = -\int_{b}^{a}f(x)dx which says swapping the limits of integration will have us swap the sign out front.

--------

Furthermore,

\displaystyle 0.5\int_{-2}^{0}e^{u}du = \frac{1}{2}\left[e^u+C\right]_{-2}^{0}\\\\\\= \frac{1}{2}\left[(e^0+C)-(e^{-2}+C)\right]\\\\\\= \frac{1}{2}\left[1 - \frac{1}{e^2}\right]

In short,

\displaystyle \int_{0}^{1}e^{-2x}dx = \frac{1}{2}\left[1 - \frac{1}{e^2}\right]

This points us to choice C as the final answer.

5 0
2 years ago
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