Given:
Volume of cuboid container = 2 litres
The container has a square base.
Its height is double the length of each edge on its base.
To find:
The height of the container.
Solution:
We know that,
1 litre = 1000 cubic cm
2 litre = 2000 cubic cm
Let x be the length of each edge on its base. Then the height of the container is:
The volume of a cuboid is:
Where, l is length, w is width and h is height.
Putting 
, we get
Divide both sides by 2.
Taking cube root on both sides.
![\sqrt[3]{1000}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1000%7D%3Dx)
Now, the height of the container is:
Therefore, the height of the container is 20 cm.
Answer:
all values of b
Step-by-step explanation:
6b < 36 or 2b + 12 > 6.
First solve the one on the left
6b < 36
Divide by 6
6b/6 < 36/6
b <6
Then solve the one on the right
2b + 12 > 6
Subtract 12 from each side
2b+12-12 >6-12
2b >-6
Divide by 2
2b/2 >-6/2
b >-3
b<6 or b >-3
Rewriting
b>-3 or b<6
b > -3 is an open circle at -3 with a line going to the right
b < 6 is an open circle at 6 with a line going to the left
The or means we add the lines together
We have a line going from negative infinity to infinity
all values of b
Answer: 5x - 2y = 8
y+1=5/2(x-2)+2
multiply the each side by 2 to get rid of the fraction
2 (y+1) = (5/2 (x-2) +2 )2
2y+2=5(x-2)+4
now distribute the 5
2y+2=5x-10+4
subtract the two from each side
2y=5x-10+4-2
add like terms
2y=5x-8
subtract 5x from each side
2y-5x=-8
multiple the whole equation by -1 to make the 5x a positive
-2y+5x=8
hope this helps!
Answer:
- <u>The value of N is 8</u>
<u></u>
- <u>The value of the angles is 48º</u>
Explanation:
The two indicated angles are supplementary because they could be drawn as two interior angles on the same side of two parallel sides cut by a transversal.
Thus, those measure of those two angles add up 180º, which lets you to write an equation and solve for N:
And the value of the angles is:
- 8N - 16 = 8(8) - 16 = 48, or
Answer: 8
Step-by-step explanation:
