Answer:
a) Statement is true
b) Statement incorrect. Company goal is to attend customer at 190 second at the most. So test should be one tail test (right)
c) We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
Step-by-step explanation:
a) as the significance level is = 0,02 that means α = 0,02 (the chance of error type I ) and the β (chance of type error II is
1 - 0.02 = 0,98
b) The company establishe in 190 seconds time for customer at its ticket counter (if this time is smaller is excellent ) company is concerned about bigger time because that could be an issue for customers. Therefore the test should be a one test-tail to the right
c) test statistic
Hypothesis test should be:
null hypothesis H₀ = 190
alternative hypothesis H₀ > 190
t(s) = ( μ - μ₀ ) / s/√n ⇒ t(s) = ( 202 - 190 )/(28/√100 )
t(s) = 12*10/28
t(s) = 4.286
That value is far away of any of the values found for 99 degree of fredom and between α ( 0,025 and 0,01 ). We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
If we look table t-student we will find that for 99 degree of freedom and α = 0.02.
The equivalent fraction for 0.7 is 70/100.
You know this because 0.7 is the same as 7/10.
7/10 is the same as 70/100 when we create 7 groups of 10 (numerator) and 10 groups of 10 (denominator).
Also, placing a zero to the right of any number on the right hand side of the decimal point will not change the value.
0.70 is 70/100
Answer:
Step-by-step explanation:
<u>Given:</u>
<u>Rewrite it as:</u>
<u>Simplify the expression:</u>
Answer:
Shape: Approximately Normal
Center: 20 minutes
Variability: 6.5 minutes.
Answer:
The simplified form of 
is 
Step-by-step explanation:
Given :
We have to write the simplified form of
Consider the given expression
We know 
and 
Thus,
Simplify, we have,
Thus, The simplified form of is
