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marysya [2.9K]
3 years ago
6

How do you find and interpret the zeros of y= -2(x-3)^ + 4

Mathematics
1 answer:
Papessa [141]3 years ago
6 0
All of them. You have to subtract and also add. That will explain how you get the equation out to a zero
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Help me plz:3 tahnk you!!
soldi70 [24.7K]

Answer:

1. (1, -4) => G

2. (-4, 1) => A

3. (0, -2) => H

4. (3, 5) => D

5. (2, 0) => F

Step-by-step explanation:

1. (1, -4) => when x = 1, y = -4 at point G

2. (-4, 1) => when x = -4, y = 1 at point A

3. (0, -2) => when x = 0, y = -2 at point H

4. (3, 5) => when x = 3, y = 5 at point D

5. (2, 0) => when x = 2, y = 0 at point F

6 0
3 years ago
If g(x) = x2 + 2, find g(3). (2 points) 9 8 11 6
Igoryamba

For this case we have a function of the form y = g (x)

Where:

g (x) = x ^ 2 + 2

We must find the value of the function when x = 3. Then we substitute:

g (3) = 3 ^ 2 + 2\\g (3) = 9 + 2\\g (3) = 11

Thus, the value of the function when x = 3 is y = 11

Answer:

g (3) = 11

Option C

7 0
3 years ago
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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The answer to this question  is a=2   

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