Answer:
300
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form 
or 
where
k is the constant of variation
in this problem we have
the point 
so
substitute
therefore
<u>the answer is</u>
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
420 cm, 4.3 meters, 4600 mm, 0.04 km
Step-by-step explanation:
We can solve this by converting each to the same unit. I will be using meters.
0.04 km
1 km = 1000 meters
1000 meters / 1 km = 1
multiply 0.04 km by 1 = 1000 meters / 1 km , keeping the km at the bottom to cross out
0.04 km * 1000 meters / 1 km = 40 meters
420 cm
100 cm = 1 meter
1 meter / 100 cm = 1
multiply 420 cm by this, keeping cm at the bottom so it crosses out
420 cm * 1 meter / 100 cm = 4.2 meters
4600 mm
1000 mm = 1 meter
1 meter / 1000 mm = 1
4600 mm * 1 meter / 1000 mm = 4.6 meters
Therefore, our order is
420 cm, 4.3 meters, 4600 mm, 0.04 km
Answer:
36
Step-by-step explanation:
18=a/2
2*18=a
36=a
