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3 years ago

18% of what number is 43?

2 answers:

7 0

18% of 238.8889 is 43.

Convert the percentage (18) to a decimal by dividing it over 100:
$\frac{18}{100} = 0.18$

Divide 43 over 0.18:
 $\frac{43}{0.18} = 238.8889$

DerKrebs [107]3 years ago

7 0

18% of 43

18/100 = .18

.18 * 43 = 7.74

Answer: About 8

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Mike got in and elevator and whent down 3 floors. he meant to go to a lower level,so he stayed on the elevator and when down 3 m

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It is negative six because down three is -3 so 3+3 =6 but the numbers are negative so the answer is -6

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3 years ago

The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is th

Dafna11 [192]

Answer:

$a + b \geq 30$

$b - a \geq 10$

Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

$a + b \geq 30$

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

$b - a \geq 10$

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

$a + b \geq 30$

$b - a \geq 10$

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3 years ago

How to subtract with renaming fractions

givi [52]

1.Rename with common denominators.
2.Regroup the first fraction.
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3 0

3 years ago

2x+3y=15 x+y=6 find values for x and y

MatroZZZ [7]

Answer:

(x, y) = (3, 3)

Step-by-step explanation:

Subtract double the second equation from the first.

(2x +3y) -2(x +y) = (15) -2(6)

y = 3 . . . . . . . . simplify

Use the second equation to find x.

x = 6 -y = 6 -3 = 3

The values of x and y are both 3.

8 0

2 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis

Licemer1 [7]

Answer:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

7 0

2 years ago