Show that area under multivariate normal distribution over the whole range in unity. Find characteristics function of multivaria
1 answer:
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Answer:
- down
- maximum
- x=2; (2, 1), -3
Step-by-step explanation:
1. The negative leading coefficient (-2) tells you the parabola opens downward.
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2. The fact that the parabola opens downward tells you the vertex is a maximum.
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3. For quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For this parabola, that is x = -4/(2(-1)) = 2. The y-value of the vertex is f(2) = -2^2+4(2)-3 = -4+8-3 = 1. The y-intercept is the constant, c = -3.
- axis of symmetry: x = 2
- vertex: (2, 1)
- y-intercept: (0, -3)
