90 points where at least two of the circles intersect.
<h3>Define circle.</h3>
A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the centre.
Given,
Four distinct circles are drawn in a plane.
Start with two circles; they can only come together in two places. The third circle contacts each of the previous two circles in two spots each, bringing the total number of intersections up to four with the addition of a third circle. The total number of intersections will rise by another 6 when a fourth circle intersects the first three. And the list goes on.
As a result, we get a recognizable, regular pattern: for each additional circle, there are two more intersections overall than in the circle before it.
The total number of intersections can be expressed as the sum because the maximum number of intersections of 10 circles must occur when each circle contacts every other circle in 2 places each.
2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 = 90.
90 points where at least two of the circles intersect.
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I believe the answer would be 24 square units
Answer:
Beam stick out = 2.09 ft
Step-by-step explanation:
Given:
Length of wooden beam = 12 ft
Side of bed = 5.5 ft by 8 ft by 2 ft
Find:
Length of wooden beam needed.
Computation:
Length of wooden beam needed = 9.91 ft
Beam stick out = 12 ft - 9.91 ft
Beam stick out = 2.09 ft
