12,<br> Is this a discrete?

How do you find the surface area of a cube

lianna [129]

Find the surface area of one side and multiply it by 6

6 0

2 years ago

What is the value of a for the following circle in general form?<br> x2 + y² + ax + by+c=0

motikmotik

Answer:

Step-by-step explanation:

x2+y2+ax+by+c=0

Step 1: Add -by to both sides.

ax+by+x2+y2+c+−by=0+−by

ax+x2+y2+c=−by

Step 2: Add -x^2 to both sides.

ax+x2+y2+c+−x2=−by+−x2

ax+y2+c=−bax+y2+c+−y2=−by−x2+−y2

ax+c=−by−x2−y2

Step 4: Add -c to both sides.

ax+c+−c=−by−x2−y2+−c

ax=−by−x2−y2−c

Step 5: Divide both sides by x.

ax

x

=

−by−x2−y2−c

x

a=

−by−x2−y2−c

x

y−x2

6 0

2 years ago

Read 2 more answers

The reflection of a Quadrant II point is located in Quadrant I. Assuming no error was made, what kind of reflection occurred?

gizmo_the_mogwai [7]

Answer:

A reflection across the y- axis

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y) → (-x, y)

A point in the second quadrant (- x, y)

Under reflection in the y- axis is (x, y) ← point in first quadrant

3 0

2 years ago

Read 2 more answers

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

3 years ago

A number between

Dovator [93]

it's 24

Good luck!!!!! (:

8 0

2 years ago

Read 2 more answers

12, Is this a discrete?