4^x + 6^x = 9^x
4^x + 6^x - 9^x = 0
2^2x + (2×3)^x - 3^2x = 0
2^2x + 2^x×3^x - 3^2x = 0
(⅔)^2x + (⅔)^x - 1 = 0
let t = ( ⅔)^x
t² + t - 1 = 0
t = (-1+√5 ) / 2
(⅔)^x = (-1+√5 ) / 2
x = Log base ⅔ ((-1+√5 ) / 2 )
x = 1.18681
Answer:
Money invested in CD account: $2000
Money Invested in Savings Bond: $4000
Step-by-step explanation:
Given
Total amount=$6000
Let
x be the amount invested in CD at 4%
And
6000-x be the remaining amount invested in savings bond at 7%
So mathematically writing
0.04x+0.07(6000-x)=360
0.04x+420-0.07x=360
-0.03x+420=360
-0.03x=360-420
-0.03x= -60
x= -60/(-0.03)
x=$2000
So the amount invested in CD is $2000.
And the amount invested in savings bond is:
=6000-x
=6000-2000
=$4000 ..
Your answers are? Please give the answers to this question. Then I may help
Answer:
Laws of Exponents. When multiplying like bases, keep the base the same and add the exponents. When raising a base with a power to another power, keep the base the same and multiply the exponents. When dividing like bases, keep the base the same and subtract the denominator exponent from the numerator exponent.
Step-by-step explanation:
Well not exactly a way to explain the answer.
