Which equations could be used to solve for the unknown lengths of △ABC? Check all that apply.
2 answers:
Answer:
sin(45°)= AC/9
cos(45°)= BC/9
Step-by-step explanation:
This is a right angle triangle:
∠ABC =∠CAB = 45°
Now
AC= CB
AB = 9 units.
We will apply sines:
sine(45°)= AC/AB
We know that AB = 9 units.
So substitute the value of side AB
sin(45°)= AC/9
Now apply cos(45°)
cos(45°)= BC/AB
Again substitute the value of AB:
cos(45°)= BC/9
Thus the answer is
sin(45°)= AC/9
cos(45°)= BC/9 ....
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Answer:
11/6 or 1.8333333333
Step-by-step explanation:
=
Cross Multiply:
7 x 6 = 42
9 (2x+1)
42 = 9(2x+1)
42 = 18x + 9
Then, isolate the variable. In order to do so, subtract 9 from both sides.
33 = 18x
Now, divide by 18 (to find x)
33/18 =
1.8333333 or 11/6