Answer:
y = -0.6x^2 + 5x + 6
Step-by-step explanation:
First, find the equation of a linear line that passes through the points (0,6) and (3, 15.6) in the slope intercept form, y = mx + b. We know that the line has a y-intercept of 6, so b = 6. Substitute 3 for x, 15.6 for y, and 6 for b to find m.
y = mx + b
15.6 = 3m + 6
9.6 = 3m
m = 3.2
y = 3.2x + 6
y = a(x - 0)(x - 3) + 3.2x + 6
y = a(x)(x - 3) + 3.2x + 6
Finally, substitute 10 for x and -4 for y in the equation above to find a.
-4 = a(10)(10 - 3) + 3.2*10 + 6
-4 = a(10)(7) + 32 + 6
-4 = 70a + 38
-42 = 70a
a = -0.6
Simplify to write in standard form.
y = -0.6(x)(x - 3) + 3.2x + 6
y = -0.6x^2 + 5x + 6
The Cosine Law:
c² = a² + b² - 2 a b cos C
14² = 28² + b² - 56 · b · √3/2
196 = 784 + b² - 28√3 b
b² - 28√3 b + 588 = 0
b 1/2 = (28√3 +/- √(2352 - 2352 )) / 2 = 28√3 / 2 = 14√3
Answer:
The given measurements determine one triangle.
$10 because 2 and 3 add together and subtract 15 equals 10
529/23=23 so the width of the triangle is 23 also
Answer:
relationship between hypotenuse and perpendicular is given by sin angle
sin60=p/h
√3/2=a/16
√3/2×16=a
8√3=a
option C is your answer